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Subj:.....The
Boxer's Puzzle (S619)
From the book
"Mathematical Puzzles of Sam Loyd"
Edited by Martin Gardner
From: Dover Publications in 1959
What is the best play
and how many boxes
will it win?
Here is a familiar
little puzzle game from the East, played
upon lines very similar
to the well known game of "Tit-Tat-
Toe, three in a row."
One of the Chinese girls writes sixteen
letters on a slate
in four rows, as shown. After marking a
straight dash from
A to B, she passes the slate to her opponent,
who connects E to
A. If the first player should now connect
E to F, the other
player would connect B with F and score
"one box," and have
the right to play again. But they have
played so well that
neither one has yet scored a box, although
each played six times.
The game is reaching a critical point
where one of them
must win, for there are no draws in this
game.
The little maiden
sitting down has to play now, and if she
connects M to N her
opponent could score four boxes in one
run, then having
the right to one more play, would connect H
and L which would
win all the rest. What play would you now
advise, and how many
boxes will it win against the best possi-
ble play of the second
player?
Remember, when a player
scores a "box" he playes again.
Suppose for example
a player marks from D to H. Then the
second player marks
from H to L, and no matter what mark the
first player makes,
the second player scores all nine boxes
without stopping.
It is a game that calls for considerable
skill as you will
discover after trying a few games.
Click below to read
Sam Loyd's solution. |