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 Subj:.....Annual Picnic (S627)           From the book              "Mathematical Puzzles of Sam Loyd"           Edited by Martin Gardner            From: Dover Publications in 1959 Photo from BakerRanchLava.com
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When they started off on the great annual picnic, every
wagon carried exactly the same number of persons.  Half
way to the grounds ten wagons broke down, so it was
necessary for each remaining wagon to carry one more
person.

When they started for home it was discovered that
fifteen more wagons were out of commission, so on the
return trip there were three persons more in each wagon
than when they started out in the morning.  How many
people attended the great annual picnic?

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 Finger pointing down from darrell94590 on 1/2/2006
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 Drawing from Ripleys-Believe It Or Not
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THE SOLUTION

Let N = the number of people originally in each wagon
and W = the number of wagons originally going to the picnic.

The equation for going to the picnic is

W N = ( N + 1 ) ( W - 10 )

and the equation for returning from the picnic is

W N = ( N + 3) ( W - 25 )
 Using elementary Algebra to solve two equations with two unknowns yields N = 9 and W = 100. Therefore there were 900 people at the annual picnic. Photo from BakerRanchLava.com

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