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The solution
comes from
Subj:.....A
Clock Puzzle (S486, S601)
From the book
"Mathematical Puzzles of Sam Loyd"
Edited by Martin Gardner
From: Dover Publications in 1959
If the minute hands
goes twelve times faster than the hour
hand, then they will
meet eleven times during every 12-hour
period. By
taking the eleventh part of 12 hours for our
constant, we find
there will be a meeting of hands every
65 and 5/11 minutes,
or every 65 minutes, 27 and 3/11
seconds. The
hands will next come together, therefore, at
5 minutes, 27 and
3/11 seconds past 1 o'clock. |